bring the x multiplicating to the other side
[tex]12=\frac{15x}{33}[/tex]clear the equation for x
[tex]\begin{gathered} \frac{12}{15}\cdot33=x \\ x=\frac{132}{5}=26.4 \end{gathered}[/tex]prove the x
[tex]\begin{gathered} \frac{12}{26.4}=\frac{5}{11} \\ \frac{15}{33}=\frac{5}{11} \\ \frac{5}{11}=\frac{5}{11} \end{gathered}[/tex]x must be equal to 26.4
