SOLUTION:
The manager has to clear an area equivalent to the area of the merry go round.
The area of the merry go round is;
[tex]\begin{gathered} A=\pi r^2=\pi(\frac{d}{2})^2 \\ =\pi(9^2) \\ =254.47ft^2 \end{gathered}[/tex]
Thus, the manager has to clear 254.47 square feet of land.
