Respuesta :
In this question, we need to find the probability of an event in which the final result depends on one of the events to happen. It is a conditional probability.
We have a bag with the following amount of different candies:
• 5 yellows candies
,• 11 red candies
,• 4 green candies
,• 12 blue candies
,• 7 brown candies.
If we add all of these candies, we have a total of 39 candies.
Now, we need to find the probability of pulling a green candy from the bag is:
[tex]P(green)=\frac{4}{39}_{}[/tex]Since Julie ate one of the candies, there will be 38 candies in the bag after that event. Now the probability of pulling a blue candy is:
[tex]P(\text{blue)}=\frac{12}{39}[/tex]Hence, the probability, in this case, is the product of both previous probabilities as follows:
[tex]\begin{gathered} P=\frac{4}{39}\cdot\frac{12}{39}_{}\approx0.0323886639676\approx3.24\% \\ \end{gathered}[/tex]If we round the probability to the nearest percent, we have that the probability will be, approximately, 3%.
In summary, we have that the probability, to the nearest percent, that Julie pulls a green M and M from the bag, eats it, then pulls a blue candy from the bag is, approximately, 3% (option C.)
