[tex]\begin{gathered} \frac{1}{2}\text{ x + 1 = }\frac{3}{2}x-8 \\ \frac{1}{2}\text{ x + 1 }-\frac{3}{2}x\text{= }-8\text{ (Subtracting 3/2x from both sides of the equation)} \\ \frac{1}{2}\text{ x }-\frac{3}{2}x\text{= }-8-\text{ 1 (Subtracting }1\text{ from both sides of the equation)} \\ -\frac{2}{2}x\text{= }-9\text{ (Adding like terms)} \\ -x=-9\text{ (Simplifying)} \\ x=9\text{ (Multiplying by -1 on both sides of the equation)} \\ \text{The answer is 9} \end{gathered}[/tex]
