we are gonna type the equation over here..
[tex]3a-21b+18c=0\text{?}[/tex]if it is equal to zero, we want to find that number that is common in all factors..
for the first one we only have..
[tex]3a;\text{ then the only number that appear here is 3}[/tex]for the second factor we have
[tex]-21b\text{ = (-7)(3)b ; we can express like this, in a multi}plication\text{ of -7 and 3}[/tex]and for the latest:
[tex]18c\text{ = (6)(3)c}[/tex]placing,
[tex](3)a-(7)(3)b+(6)(3)c=0[/tex]The number in common in all factors is 3; then your answer will be:
[tex]3(a-7b+6c)=0[/tex]