Respuesta :

we are gonna type the equation over here..

[tex]3a-21b+18c=0\text{?}[/tex]

if it is equal to zero, we want to find that number that is common in all factors..

for the first one we only have..

[tex]3a;\text{ then the only number that appear here is 3}[/tex]

for the second factor we have

[tex]-21b\text{ = (-7)(3)b ; we can express like this, in a multi}plication\text{ of -7 and 3}[/tex]

and for the latest:

[tex]18c\text{ = (6)(3)c}[/tex]

placing,

[tex](3)a-(7)(3)b+(6)(3)c=0[/tex]

The number in common in all factors is 3; then your answer will be:

[tex]3(a-7b+6c)=0[/tex]