To find the equation of the line we must use the next equation
[tex]y-y_1=m(x-x_1)[/tex]First, we need to replace the two points to find the slope (m) of the line
[tex]\begin{gathered} 6-4=m(4-3) \\ m=\frac{6-4}{4-3}=\frac{2}{1}=2 \end{gathered}[/tex]Then, we must replace on the points and the slope in the initial equation
[tex]\begin{gathered} y-6=2(x-4) \\ y-6=2x-8 \\ y-6-2x+8=0 \\ y-2x+2=0 \end{gathered}[/tex]Finally, the equation of the line is
[tex]y-2x+2=0[/tex]