Given:
ABCD is a trapezoid.
[tex]\bar{BC}\bar{||AD}[/tex][tex]BC=20in\text{ and }AD=28in.[/tex][tex]The\text{ distance between }\bar{BC}\text{ and }\bar{AD}\text{ is 7 in.}[/tex]
Required:
We need to find the area of the trapezoid ABCD.
Explanation:
The side length of the first base, a =20 in.
The side length of the second base, b =28 in.
The height of the trapezoid, h =7 in.
Consider the area of the trapezoid formula.
[tex]A=\frac{a+b}{2}h[/tex]
Substitute a =20 , b =28, and h =7 in the formula.
[tex]A=\frac{20+28}{2}\times7[/tex][tex]A=168in^3[/tex]
Final answer:
[tex]A=168in^3[/tex]
