Solution
In ΔFGH, line FG ║line IJ
And the following dimensions are given
[tex]\begin{gathered} \text{IF}=15 \\ HI=12 \\ JG=20 \\ HJ\text{ is unknown} \end{gathered}[/tex]
To find HJ, usingthe formula for the ratio of similar triangles, i.e
[tex]\frac{HI}{IF}=\frac{HJ}{JG}[/tex]
Substitute the values into the formula above
[tex]\frac{12}{15}=\frac{HJ}{20}[/tex]
Crossmultiply and solve for HJ
[tex]\begin{gathered} 12\times20=HJ\times15 \\ \text{Divide both sides by 15} \\ HJ=\frac{12\times20}{15} \\ HJ=16\text{ units} \end{gathered}[/tex]
Hence, HJ is 16 units.
