SOLUTION:
Case: Probability (Sample space)
Given:
Sample space, S = (2,3,4,5,6,7,8,9,10,11,12)
event A = {5,6,7,8,9)
Required: Get the list of elements for A complement and the probability of obtaining A complement.
Method:
A complement simply represents items found in the Sample space, S but not in event A.
It includes:
[tex]A^c=\text{ (2,3,4,10,11,12)}[/tex]
The probability to obtain event A complement will be:
[tex]\begin{gathered} Pr(A)+Pr(A^c)\text{ = 1} \\ \text{When you add two opposite events, it gives 1} \\ Pr(A^c)=\frac{numberofeventforA^c}{\nu mber\text{ of events for sample space}} \\ Pr(A^c)=\text{ }\frac{6}{11} \end{gathered}[/tex]
Final answer:
[tex]\begin{gathered} A^c=\text{ (2,3,4,10,11,12) AND} \\ Pr(A^c)=\text{ }\frac{6}{11} \end{gathered}[/tex]
