Given data:
The mass of marshmallow launcher toy is M=1 kg.
The mass of marshmallow is m=0.05 kg.
The angle with horizontal is θ=60°.
The speed of marshmallow is v=10 m/s.
Considering the velocity of marshmallow is u.
Applying the conservation of momentum between the marshmallow and toy,
[tex]\begin{gathered} Mu=mvcos\theta \\ (1)u=(0.05)(10)cos60\degree \\ u=0.25\text{ m/s} \end{gathered}[/tex]Thus, the velocity of marshmallow is 0.25 m/s.
