[tex]\begin{gathered} \text{ warehouse has 8000 sq ft, half of which is usable for stocking} \\ \text{this gives us 4000 sq ft} \\ \text{ it has a height of 20 ft, which gives us} \\ (4000ft^2)(20ft)=80000ft^3\text{ of volume} \\ \text{ The volume of the box is } \\ (36in)(36in)(15in)=19440in^3 \\ \text{ Convert it cubic inches to cubic foot} \\ 19440in^3\cdot(\frac{1ft}{12in})^3=11.25ft^3 \\ \text{ Divide the working volume of the warehouse by the volume of the box} \\ \frac{80000ft^3}{11.25ft^3}=7111.1111 \\ \text{Round it off to a whole number} \\ 7111 \\ \text{ Therefore, we can have a maximum of 7111 box of rims that we can stock} \\ \text{ in the warehouse} \end{gathered}[/tex]
