1) The angle formed by QR and the base is shown below
The above triangle is a right angle triangle. The angle between QR and the base is #. We would find # by applying the tangent trigonometric ratio which is expressed as
tan # = opposite side/adjacent side
From the triangle,
opposite side = 1
adjacent side = 0.6
tan # = 1/0.6 = 1.67
# = tan^-1(1.67)
# = 59.09
The angle between segment QR and the base is 59.09 degrees
ii) The angle formed by QU and the base is shown below
We would find QU by applying pythagorean theorem which is expresses as
hypotenuse^2 = opposite side^2 + adjacent side^2
Thus, we have
[tex]\begin{gathered} QR^2=1^2+0.6^2\text{ = 1.36} \\ QR\text{ = }\sqrt[]{1.36\text{ }}\text{ = 1.17} \end{gathered}[/tex]
We would find # by applying the tangent trigonometric ratio again. Thus, we have
Tan # = 1.17/24 = 0.04875
# = tan^-1(0.04875)
# = 2.79
The angle between line segment QU and the base is 2.79 degrees
iii) The angle formed between line segment QN and the base is shown below
We would find # by applying the tangent ratio again. This, we have
tan # = 1/24 = 0.04167
# = tan^-1(0.04167)
# = 2.39
The angle formed between line segment QN and the base is 2.39 degrees
