Given:
The length of ribbon Jase has, l=5 1/3 feet
The length of ribbon needed to make one bracelet, L=2/3 feet.
The number of bracelets Jase can makes is,
[tex]\begin{gathered} n=\frac{l}{L} \\ =\frac{5\frac{1}{3}}{\frac{2}{3}} \\ =\frac{\frac{5\times3+1}{3}}{\frac{2}{3}} \\ =\frac{\frac{16}{3}}{\frac{2}{3}} \\ =\frac{16}{2} \\ =8 \end{gathered}[/tex]Therefore, Jase can make 8 bracelets.
