[tex]\begin{gathered} \int ^e_1\frac{8}{x}dx \\ =8\lbrack\ln |x|\rbrack^e_1 \\ \text{computing for the boundaries,} \\ \lbrack\ln |x|\rbrack^e_1=1 \\ \text{thus} \\ 8\lbrack\ln |x|\rbrack^e_1=8\cdot1=8 \\ \\ \text{therefore,} \\ \int ^e_1\frac{8}{x}dx=8 \end{gathered}[/tex]