Solution
We have the following coordinates:
(0,0), (1,3), (5,0), (6,3)
We can find the distance between the vertices like this:
[tex]d=\sqrt[]{(1-0)^2+(3-0)^2}=\sqrt[]{10}[/tex][tex]d=\sqrt[]{(5-0)^2+(0-0)^2}=5[/tex][tex]d=\sqrt[]{(6-0)^2+(3-0)^2}=\sqrt[]{45}[/tex][tex]d=\sqrt[]{(5-1)^2+(0-3)^2}=5[/tex][tex]d=\sqrt[]{(6-5)^2+(3-0)^2}=\sqrt[]{10}[/tex][tex]d=\sqrt[]{(6-0)^2+(3-0)^2}=\sqrt[]{45}[/tex]Then the correct answer for this case is:
D. Parallelogram
