In circle J with mZHJK = 112 and HJ = 6 units find area of sector HJK. Round to the nearest hundredth.

Answer:
The area of the sector is 35.17 sq. units
Explanation:
Given that
HJ = 6 units. This is the radius, r
And area of sector is given as:
[tex]\frac{Central\text{ Angle}}{360}(Area)[/tex]Where
[tex]\text{Area}=\pi r^2[/tex]Using these, we have:
[tex]\frac{112}{360}(6^2\pi)[/tex]Evaluating, we have:
[tex]\begin{gathered} 11.2\pi \\ =11.2\times3.14 \\ =35.168 \\ \approx35.17 \end{gathered}[/tex]