for this
we will calculate the slopes
for AB line point A is (3, -1) and B (2, -4)
so the slope is
[tex]m=\frac{-4-(-1)}{2-(3)}=\frac{-3}{-1}=3[/tex]
for line A'B' the point A' is (-1, -3) and B' is (-4, - 2)
so the slope i s
[tex]m=\frac{-2-(-3)}{-4-(-1)}=\frac{1}{-3}[/tex]
multiply both slope
[tex]=\frac{1}{-3}\times3=-1[/tex]
the product of both the slope is -1
so they are at 90 degrees or perpendicular to each other,
so the answer is option A.
