SOLUTION:
We are to find the equation line parallel y=-4/5x+12 passing through (-6,2).
From the above equation line the slope (m) is - 4/5.
[tex]\begin{gathered} y-y_1=m(x-x_1)_{} \\ \text{Where x}_1=-6_{} \\ y_1=\text{ 2} \end{gathered}[/tex][tex]\begin{gathered} y-y_1=m(x-x_1) \\ y\text{ - 2 = -}\frac{4}{5}(x\text{ - (-6))} \\ y-2\text{ = -}\frac{4}{5}(x\text{ + 6)} \\ y\text{ = -}\frac{4}{5}(x\text{ + 6) + 2} \\ \\ y\text{ = -}\frac{4}{5}x\text{ - }\frac{4}{5}(\text{6) + 2} \\ \\ y\text{ = -}\frac{4}{5}x\text{ - }\frac{24}{5}\text{ + }\frac{2}{1} \\ \\ y\text{ = -}\frac{4}{5}x\text{ - }\frac{14}{5} \end{gathered}[/tex]
