To write the equation in standard form:
Step 1. Multiply the expression by 6
[tex]\begin{gathered} (\frac{8}{3}y=\frac{5}{6}x-2)\cdot6 \\ 16y=5x-12 \end{gathered}[/tex]Step 2. Clear the independent term
[tex]\begin{gathered} 16y=5x-12 \\ 16y-5x=-12 \end{gathered}[/tex]The equation in standard form is 16y-5x=-12
