The first step to answer this question is to use the molar mass of HNO3 to convert the given grams of this substance to moles (MM=63.0g/mol):
[tex]63.0g\cdot\frac{mol}{63.0g}=1mol[/tex]Now, divide the moles of solute by the kg of solvent to find the molality of the solution:
[tex]m=\frac{1mol}{0.500kg}=2m[/tex]The molality of the solution is 2m.
