1)
Given:
Required:
We need to find the value of x.
Explanation:
Recall that the corresponding sides of similar triangles are proportional.
12m and 6m are corresponding sides of the given similar triangles
16m and x are corresponding sides of the given similar triangles
The proportion of the sides can be written as follows.
[tex]\frac{12}{6}=\frac{16}{x}[/tex][tex]2=\frac{16}{x}[/tex]
Use the cross-product method.
[tex]2x=16[/tex][tex]\frac{2x}{2}=\frac{16}{2}[/tex][tex]x=8m.[/tex]
2)
Given:
18cm and 30cm are corresponding sides of the given similar triangles.
x and 25 cm are corresponding sides of the given similar triangles.
Required:
We need to find the value of x.
Explanation:
Recall that the corresponding sides of similar triangles are proportional.
The proportion of the sides can be written as follows.
[tex]\frac{18}{30}=\frac{x}{25}[/tex]
Multiply both sides of the equation by 25.
[tex]\frac{18\times25}{30}=\frac{x}{25}\times25[/tex][tex]15=x[/tex][tex]x=15cm[/tex]
3)
Given:
x and 21m are the corresponding sides of the given similar triangles.
32m and 24m are the corresponding sides of the given similar triangles.
Required:
We need to find the value of x.
Explanation:
Recall that the corresponding sides of similar triangles are proportional.
The proportion of the sides can be written as follows.
[tex]\frac{x}{21}=\frac{32}{24}[/tex]
Multiply both sides of the equation by 21.
[tex]\frac{x}{21}\times21=\frac{32}{24}\times21[/tex][tex]x=28m[/tex]
4)
Given:
12in and 15in are the corresponding sides of the given similar triangles.
x and 40in are the corresponding sides of the given similar triangles.
Required:
We need to find the value of x.
Explanation:
Recall that the corresponding sides of similar triangles are proportional.
The proportion of the sides can be written as follows.
[tex]\frac{12}{15}=\frac{x}{40}[/tex]
Multiply both sides of the equation by 40.
[tex]\frac{12}{15}\times40=\frac{x}{40}\times40[/tex][tex]x=32in[/tex]
Final answer:
1)
[tex]x=8m.[/tex]
2)
[tex]x=15cm[/tex]
3)
[tex]x=28m[/tex]
4)
[tex]x=32in[/tex]
