Answer:
34, 35, 36
Explanation:
Let the first consecutive integer =x
The next two consecutive integers are: x+1 and x+2
The sum of the first two integers =x+(x+1)
32 more than the third integer = (x+3)+32.
Therefore, we have the equation
[tex]x+(x+1)=(x+3)+32[/tex]We then solve for x.
[tex]\begin{gathered} 2x+1=x+35 \\ \text{Collect like terms} \\ 2x-x=35-1 \\ x=34 \end{gathered}[/tex]The three consecutive integers are: 34, 35 and 36.
