To determine the width of swtiches in a box
Step 1: Let the number of switches = 3
[tex]3(2\text{ }\frac{\text{1}}{2}\text{)}=3(\frac{5}{2})=\frac{15}{2}[/tex]Step 2: Let the clearance between switches= 2
[tex]2(1\frac{1}{4})=2(\frac{5}{4})[/tex]Step 3: Let the number between the edge and switch=2
[tex]2(3\frac{7}{8})=2(\frac{31}{8})[/tex]Therefore the width of the box will be
[tex]\begin{gathered} \frac{15}{2}+\frac{5}{2}+\frac{31}{4} \\ \frac{30+10+31}{4} \\ =\frac{71}{4} \\ =17.75 \end{gathered}[/tex]Hence the box should be 17.75 inches wide
