Given:
The triangle ABC is,
Consider the traingle ABC and ADE,
[tex]\begin{gathered} BC\parallel DE\text{ ans AC is the transversal.} \\ \Rightarrow\angle B=\angle D\text{ and }\angle C=\angle E \\ \text{Also, }\angle A=\angle A\text{ ( common angle)} \end{gathered}[/tex]
Hence, the traingles are congruent by AA property.
Answer:
[tex]\Delta ABC\approx\Delta ADE\text{ by AA}[/tex]
