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A concession stand at a football game sells hamburgers and boxes of candy. Jeremy buys a total of 16 items. The number of candy boxes he buys is four
less than three times as many hamburgers. Which system of equations models this situation if he bought h hamburgers and c boxes of candy?
3h - 4 = 16
h-C = 16
C = 3-4
h+C = 16
h = 4 - 30
h + C + 4-3 = 16
h = 3c - 4
h+c=16

Respuesta :

Let x and y be the number of hamburgers and boxes sold; then,

[tex]\begin{gathered} x+y=16 \\ y=3x-4 \end{gathered}[/tex]

Substitute h=x and C=y;

[tex]\Rightarrow\begin{cases}h+C=16 \\ C=3h-4\end{cases}[/tex]

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