SOLUTION
Given the question on the question tab;
[tex]a_n=3n+16[/tex][tex]\begin{gathered} a_1=3(1)+16=19 \\ a_2=3(2)+16=22 \\ a_3=3(3)+16=25 \end{gathered}[/tex][tex]The\text{ sequence has the common difference of 3.}[/tex]
The terms of the sequence are:
[tex]19,\text{ 22, 25,..., 46, 49, 52, 55, 58, 61, 64, 67,....}[/tex]
Final answer:
