How do we determine the equation with the given roots?

ANSWER
[tex]x^2-4=0[/tex]EXPLANATION
The intercept (roots) form of a quadratic equation is:
[tex]a(x-p)(x-q)=0[/tex]where a = leading coefficient
p, q = roots of the equation
Hence, the quadratic equation whose roots are 2 and -2 and has a leading coefficient of 1 is:
[tex]\begin{gathered} 1(x-2)(x-(-2))=0 \\ (x-2)(x+2)=0 \\ \Rightarrow x^2-2x+2x-4=0 \\ x^2-4=0 \end{gathered}[/tex]That is the answer.