Given data:
* Range of the flight given is,
[tex]R=1.02\text{ m}[/tex]* The time of the flight is,
[tex]T=1.2\text{ s}[/tex]* The height of the launch is,
[tex]H=1\text{ m}[/tex]Solution:
(a). The initial velocity of the horizontal projectile is,
[tex]\begin{gathered} R=uT \\ u=\frac{R}{T} \end{gathered}[/tex]Substituting the known values,
[tex]\begin{gathered} u=\frac{1.02}{1.2} \\ u=0.85ms^{-1} \end{gathered}[/tex]Thus, the initial velocity of the projectile is 0.85 meter per second.
