Solution:
Consider the polynomial:
[tex]8x^2+16x+8[/tex]now, to find the roots of the above equation, use the following quadratic equation:
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]in this case, we have that a = 8, b = 16 and c = 8. So, replacing the above data on the previous equation we get:
[tex]x=\frac{-16\pm\sqrt[]{16^2^{}-4(8)(8)}}{2(8)}[/tex]this gives us :
[tex]x\text{ = }-1[/tex]thus, we can conclude that the root of the given polynomial is
[tex]x\text{ = }-1[/tex]
