To answer this question, we need to plug each of the ordered pairs in the linear equation to check if they are solutions to the equation. Then, we have:
1. Ordered pair (7, 10):
[tex]3x+12y=2\Rightarrow3(7)+12(10_{})=21+120=141\ne2[/tex]
This is NOT a solution.
2. (-8, -8)
[tex]3(-8)+12(-8)=-24-96=-120\ne2[/tex]
This is NOT a solution.
3. (-7, 4)
[tex]3(-7)+12(4)=-21+48=27\ne2[/tex]
This is NOT a solution.
4. (-2, -4)
[tex]3(-2)+12(-4)=-6-48=-54\ne2[/tex]
This is NOT a solution.
Therefore, the correct option is NONE OF THE ABOVE.
