The given equation is,
[tex]\frac{1+6i}{-3+2i}[/tex]now, multiply with a conjugate -3-2i.
[tex]\begin{gathered} \frac{1+6i}{-3+2i}\cdot\frac{-3-2i}{-3-2i}=\frac{9-20i}{13} \\ =\frac{9}{13}-\frac{20}{13}i \end{gathered}[/tex]the answer is
[tex]\frac{9}{13}-\frac{20}{13}i[/tex]