ption (A) is the correct answer.
Given:
The function is,
[tex]h(t)=2^t\text{ over the interval t=1 to t=3}[/tex]The objective is to find the correct option.
At the interval t = 1,
[tex]\begin{gathered} h(1)=2^1 \\ h(1)=2 \end{gathered}[/tex]At the interval t = 3,
[tex]\begin{gathered} h(3)=2^3 \\ h(3)=8 \end{gathered}[/tex]Consider the change in factor as x and compare the results 2 and 8.
[tex]\begin{gathered} 2x=8 \\ x=\frac{8}{2} \\ x=4 \end{gathered}[/tex]Thus, the function increases by a factor of 4.
Hence, option (A) is the correct answer.
