We need to find which number is not irrational:
[tex]\begin{gathered} A)\sqrt[]{\frac{24}{6}}=\sqrt[]{4}=2\Rightarrow NOT\text{ Irrational} \\ B)\log _36=\frac{\log_{10}6}{\log_{10}3}\approx\text{1}.6309297\Rightarrow Irrational \\ C)2\sqrt[]{3}\cdot5\sqrt[]{3}=10\cdot(\sqrt[]{3})^2=10\cdot3=30\Rightarrow\text{NOT Irrational} \\ D)5\sqrt[3]{8}=5\cdot2=10\Rightarrow NOT\text{ Irrational} \end{gathered}[/tex]
The numbers A, C and D are NOT Irrationals.
