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The area of a square is decreasing at a rate of 58 square centimeters per minute. At the time when the area of the square is 81, what is the rate of change of the perimeter of the square? Round your answer to three decimal places (if necessary).

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SOLUTION

Step 1 :

In this question, we need to consider the following :

[tex]\begin{gathered} A=l^2 \\ \text{Differentiating both sides with respect to t, we have:} \\ \frac{\text{d A }}{d\text{ t}}\text{ =}\frac{d(l^2\text{ )}}{dt\text{ }}\text{ } \\ \\ \end{gathered}[/tex][tex]undefined[/tex]

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