Recall that:
[tex]\begin{gathered} a^{-n}=\frac{1}{a^n}, \\ n>0. \end{gathered}[/tex]
Notice that as
[tex]\begin{gathered} x\rightarrow-\infty, \\ 2^{x+1}\rightarrow0, \end{gathered}[/tex]
then
[tex]f(x)\rightarrow-2.[/tex]
Therefore, the graph has a horizontal asymptote with equation y=-2.
Answer:
Graph:
Asymptote:
[tex]y=-2.[/tex]
