we can make a triangle
It is a right triangle, to fnd h we can use trigonmetric ratios, for example sine
[tex]\sin (\alpha)=\frac{O}{H}[/tex]
where alpha is the reference angle, O the opposite side from the angle and H the hypotenuse
using 75° as reference angle we can replace
[tex]\sin (75)=\frac{h}{60}[/tex]
and solve for h
[tex]\begin{gathered} h=60\sin (75) \\ h=15(\sqrt[]{6}+\sqrt[]{2})\approx58 \end{gathered}[/tex]
maximum height is 58ft
