The solution is at (-5, 0)
see the graph below
Explanation:
9) To graph the equatios, we would assign values to x and get corresponding values of y
x + y = -5 ...equation 1
-x + 2y = 5 ...equation 2
when x = -6, -5, -4
when x = -6
-6 + y = -5
y = -5 + 6 = 1
when x = -5
-5 + y = -5
y = -5 + 5
y = 0
when x = -4
-4 + y = -5
y = -5 + 4
y = -1
when x = -6
-(-6) + 2y = 5
6 + 2y = 5
2y = 5 - 6
y = -1/2
when x = -5
-(-5) + 2y = 5
5 + 2y = 5
2y = 5-5
2y = 0
y = 0
when x = -4
-(-4) + 2y = 5
4 + 2y = 5
2y = 5-4
y = 1/2
plotting the graph:
The solution of the graph is at the intersection of both lines.
The solution is at (-5, 0)
