In order to solve this system of equations, let's use the value of x from the second equation in the first one:
[tex]\begin{gathered} \begin{cases}2y+3x=22 \\ x=19-3y\end{cases} \\ \\ 2y+3(19-3y)=22 \\ 2y+57-9y=22 \\ -7y=22-57 \\ -7y=-35 \\ y=\frac{-35}{-7} \\ y=5 \\ \\ x=19-3y \\ x=19-3\cdot5 \\ x=19-15 \\ x=4 \end{gathered}[/tex]