If the pressure reading of your pitot tube is 15.0 mm Hg at a speed of 200 km/h, what will it be at 700 km/h at the same altitude?Answer from book: p2= -20.4 x 10^3 N/m^2

Respuesta :

The pressure of the reading of tube is given as,

[tex]\begin{gathered} P=15\text{ mm} \\ P=0.02\text{ atm} \end{gathered}[/tex]

The relation between the before and after pressure is,

[tex]P^{\prime}=(\frac{v_2}{v_1^{}})^2P[/tex]

where v1 is the velocity of the speed initially, and v2 is the velocity at the final state.

Substituting the known values,

[tex]\begin{gathered} P^{\prime}=(\frac{700}{200})^2\times0.02 \\ P^{\prime}=0.245\text{ atm} \\ P^{\prime}=24.5\times10^{-3}Nmm^{-2} \\ P^{\prime}=24.5\times10^3Nm^{-2} \end{gathered}[/tex]

Thus, the final pressure reading of the pilot tube is

[tex]24.5\times10^3Nm^{-2}[/tex]

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