Explanation:
r = 11.6
p = 7.5
q = 9
∠R = 89 degrees
Using sine rule:
[tex]\frac{r}{Sin\text{ R}}=\frac{p}{\text{Sin P}}[/tex][tex]\begin{gathered} \frac{11.6}{\sin\text{ 89}\degree}=\frac{7.5}{\sin \text{ P}} \\ 11.6(\sin \text{ P) = 7.5(sin 89)} \end{gathered}[/tex][tex]undefined[/tex]
