Solution
We have the following equation:
(y-2)^2 = 4(x+3)
By direct comparison with the general formula:
(y-k)^2 = 4p(x-h)
We can see that the vertex is (-3, 2)
And the value of p =1
then the focus would be:
F= (-3+1, 2) = (-2,2)
Then the correct answer is:
c. (-2,2)
