Future value (A) with compounded interest:
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]P is the principal amount
r is the interest rate in decimals
n is the number of times the interest in compounded in a year
t is the time in years
For the given situation:
[tex]\begin{gathered} P=12,000.00 \\ r=\frac{9}{100}=0.09 \\ n=12 \\ t=2 \\ \\ A=12,000.00(1+\frac{0.09}{12})^{12\cdot2} \\ \\ A=12,000.00(1.0075)^{24} \\ \\ A=14,356.96 \end{gathered}[/tex]