In the given graph of line : the two coordinates are : (-4,1) and (4, -3)
The standard form of point-slope form of the line is :
[tex]y\text{ = }\frac{y_2-y_1}{x_2-x_1}(x-x_1)+y_1[/tex]Substitute the coordinates : ( -4, 1) & ( 4, - 3)
[tex]\begin{gathered} y\text{ = }\frac{y_2-y_1}{x_2-x_1}(x-x_1)+y_1 \\ \text{Substitute x}_1=-4,x_2=4,y_1=1andy_2=-3 \\ y=\frac{-3-1}{4-(-4)}(x-(-4))+1 \\ y=\frac{-4}{4+4}(x+4)+1 \\ y=\frac{-4}{8}(x+4)+1 \\ y=\frac{-1}{2}(x+4)+1 \\ y-1=-\frac{1}{2}(x+4) \end{gathered}[/tex]Answer : A)
[tex]y-1\text{ = -}\frac{1}{2}(x+4)[/tex]
