Respuesta :

We have an expression and we have to solve for n:

[tex]\begin{gathered} 0.2(4n+3)=2.2 \\ \frac{0.2}{0.2}(4n+3)=\frac{2.2}{0.2}_{} \\ 4n+3=11 \\ 4n+3-3=11-3 \\ 4n=8 \\ \frac{4}{4}n=\frac{8}{4} \\ n=2 \end{gathered}[/tex]

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