The correct options here are; A, B,
Here, we want to select the equations where x = 4 is a solution
To do this, we have to solve the equations
We proceed as follows;
[tex]\begin{gathered} a)\frac{16}{x}=\text{ 4} \\ 16\text{ = 4}\times x \\ 4x\text{ = 16} \\ x\text{ = }\frac{16}{4}\text{ = 4} \end{gathered}[/tex]
x = 4 is a solution to this, so, we select it
[tex]\begin{gathered} b)x^2\text{ = 16} \\ x\text{ = }\sqrt[]{16} \\ x\text{ = + 4 or -4} \end{gathered}[/tex]
x= 4 is also a solution, so we select it
[tex]\begin{gathered} c)\text{ 33-x = 37} \\ 33-37\text{ = x} \\ x\text{ = -4} \end{gathered}[/tex]
x = 4 is not a solution here, so we do not select it
[tex]\begin{gathered} d)\text{ 16 = 4x} \\ x\text{ = }\frac{16}{4} \\ x\text{ = 4} \end{gathered}[/tex]
x = 4 is a solution here, so we select it
[tex]\begin{gathered} e)\text{ 2(2+x) = 8} \\ 2+x\text{ = }\frac{8}{2} \\ 2+x\text{ = 4} \\ \text{ x = 4-2 = 2} \end{gathered}[/tex]
x = 4 is not a solution here, so we do not select it
