Solution:
Given;
[tex]m\angle6=75^o[/tex]
Thus;
[tex]\begin{gathered} m\operatorname{\angle}8+m\operatorname{\angle}6=180^o.............\text{ Sum of angles on a straight line} \\ \\ m\operatorname{\angle}8=180^o-75^o \\ \\ m\operatorname{\angle}8=105^o \\ \end{gathered}[/tex]
Then;
[tex]m\operatorname{\angle}8=m\operatorname{\angle}3...........\text{ Corresponding angles are equal}[/tex]
Thus;
[tex]m\operatorname{\angle}3=105^o[/tex]
