The length of a rectangle is three more than twice the width. Determine the dimensions that give a total area of 27ft squared
What are the length and width?
Remember that
the area of a rectangle is
A=L*W
we have
A=27 ft2
so
27=L*W ------> equation 1
and
L=2W+3 ----> equation 2
substitute equation 2 in equation 1
27=(2W+3)*W
solve for W
27=2w^2+3w
2w^2+3w-27=0
solve the quadratic equation using the formula
a=2
b=3
c=-27
substitute
[tex]w=\frac{-3\pm\sqrt[]{3^2-4(2)(-27)}}{2(2)}[/tex][tex]\begin{gathered} w=\frac{-3\pm\sqrt[]{225}}{4} \\ w=\frac{-3\pm15}{4} \\ \end{gathered}[/tex]therefore
W=3 and W=-18/4 (is not solution)
For W=3 ft
Fiind the value of L
L=2W+3
L=2(3)+3=9 ft
therefore
answer is
