Number 5
So for the difference of perfect squares factor with the numbers on both factors having to be the same, but one adds and one subtracts.
[tex]m^2-\frac{1}{9}[/tex][tex]\begin{gathered} \text{The formula is} \\ a^2-b^2=(a+b)(a-b)_{} \end{gathered}[/tex]
[tex]m^2-\frac{1}{9}=(m+\frac{1}{3})(m-\frac{1}{3})[/tex]
