Explanation
Let the price of one child ticket be x and the price of one adult ticket be y.
Therefore, from the given question, we will have;
[tex]\begin{gathered} x+4y=27----i \\ 4x+4y=36-----ii \end{gathered}[/tex]We can then create another equation iii from equation i
[tex]x=27-4y----iii[/tex]Substitute equation iii in equation i
[tex]\begin{gathered} 4(27-4y)+4y=36 \\ 108-16y+4y=36 \\ 108-12y=36 \\ -12y=36-108 \\ -12y=-72 \\ y=\frac{-72}{-12} \\ y=6 \end{gathered}[/tex]We can then substitute y=6 in equation iii
[tex]\begin{gathered} x=27-4(6) \\ x=27-24 \\ x=3 \end{gathered}[/tex]Answer: Cost of child ticket = $3 and Cost of adult ticket =$6
