We want to find g(2) if
[tex]g(x)=3x^2-3x+2[/tex]In other words, we must find the value of the equation when x = 2.
STEP 1
In order to do that we just replace all the x by 2:
[tex]\begin{gathered} g(x)=3x^2-3x+2 \\ \downarrow\text{ when x=2} \\ g(2)=3\cdot2^2-3\cdot2+2 \end{gathered}[/tex]STEP 2
Now, we just solve the operation:
[tex]\begin{gathered} g(2)=3\cdot2^2-3\cdot2+2 \\ \downarrow\text{ since }3\cdot2^2=3\cdot2\cdot2=12\text{ and }3\cdot2=6 \\ g(2)=12-6+2 \\ g(2)=8 \end{gathered}[/tex]Answer: g(2) = 8
